(2x+5)^1/2=7

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Solution for (2x+5)^1/2=7 equation: 


x in (-oo:+oo)

((2*x+5)^1)/2 = 7 // - 7

((2*x+5)^1)/2-7 = 0

(2*x+5)/2-7 = 0

(2*x+5)/2+(-7*2)/2 = 0

2*x-7*2+5 = 0

2*x-9 = 0

(2*x-9)/2 = 0

(2*x-9)/2 = 0 // * 2

2*x-9 = 0

2*x-9 = 0 // + 9

2*x = 9 // : 2

x = 9/2

x = 9/2

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